Question

Express 0.8 + 0. 777… + 0.4343… in the form of p/q where p and q are integers and
q ≠ 0.

Answer 1

We found a similar question to the one that you posted. Please check it out here.
​​​​​​We have0.8=810

Let x=0=0.¯¯¯7=0.777... ....(1)
∴10x=7.7 ....(2)Subtracting (1) from (2), we get
9x=7⇒x=79or0.¯¯¯7=79
Now, let y=0.¯¯¯¯¯¯43=0.4343....
∴10y=4.343 .... (3)And 1000y=434.343 ....(4)Subtracting (3) and (4), we get
990y=430⇒y=39990
∴0.4¯¯¯3=39990
Now, 0.8+0.¯¯¯7+0.4¯¯¯3=810+79+430990









=792+770+430990=1992990


So, 1992990 is of the form
pqandq≠0.