The correct option is C 553330
Let x=1.32=1.3222...(i)
Multiplying eq.(i) by 10, we have
10x=13.222..
Again, multiplying eq.(i) by 100, we have
100x=132.222........(iii)
Subracting eq.(ii) from (iii), we have
100x−10x=(132.222...)−(13.222...)
90x=119
⇒x=11990
Again, y=0.35=0.353535...
Multiply (iv) by 100, we have...(iv)
100y=35.353535...(v)
Subracting (iv) from (v), we have
100y−y=(35.353535...)−(0.353535...)
99y=35
y=3590
Now, 1.3¯¯¯2+0.¯¯¯¯¯¯35=x+y=11990+3599
=1309+350990=1659990=553330