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Question

Express 1.4191919..... in the form of pq , where p and q are integer and q 0.

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Solution

Given, the expression 1.4191919...
Let 1.4191919....=x (i).

Multiplying (i) by 10,
14.191919....=10x (ii).

Multiplying (ii) by 1000,
1419.191919....=1000x(iii).

Then, (iii)(ii)
1000x10x=1419.191919....14.191919....

990x=1405

x=1405990=281198.

Hencs, 1.4191919... in pq is 281198.

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