The correct option is A 1000=(1111101000)2.
Consider 1000. We observe that 512=29,256=28,128=27 and 26=64. Thus your get the sum
512+256+128+64=960
We are still short by 40 to reach 1000. But 40=32+8=25+23. Thus you obtain
1000=29+28+27+26+25+23
=1⋅29+1⋅28+1⋅27+1⋅26+1⋅25+0⋅24+0⋅23+0⋅22+0⋅21+0⋅20
You observe that this is precisely the binary representation of 1000. We write this 1000=(1111101000)2.