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Question

Express 1000 using base 2 and exponents.

A
1000=(1111101000)2.
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B
1000=(0111101000)2.
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C
1000=(1001101000)2.
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D
1000=(1111101011)2.
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Solution

The correct option is A 1000=(1111101000)2.
Consider 1000. We observe that 512=29,256=28,128=27 and 26=64. Thus your get the sum
512+256+128+64=960
We are still short by 40 to reach 1000. But 40=32+8=25+23. Thus you obtain
1000=29+28+27+26+25+23
=129+128+127+126+125+024+023+022+021+020
You observe that this is precisely the binary representation of 1000. We write this 1000=(1111101000)2.

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