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B
−40+7i
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C
46−9i
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D
46+9i
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Solution
The correct option is A−46+9i We know that (z1+z2)3=z31+z32+3z1z2(z1+z2). ∵(2+3i)3=23+(3i)3+3×2×3i(2+3i) =8+27i3+36i+54i2 =8−27i+36i−54[∵i3=−i,i2=−1] =−46+9i