Question

Express ${23}^2$ as sum of two consecutive numbers.

Answer 1

${23}^2=529$

Let the two consecutive be $x$ and $x+1$

$\therefore x+x+1=529$

$\Rightarrow 2x=529-1$

$\Rightarrow x=\frac{528}{2}$

$\Rightarrow x=264$

so the two consecutive numbers are 264 and $264+1=265$