Express (3×102)+(2×101)+(9×100)+(2×10−1)+(5×10−2) as a numeral.
32.925
3292.5
329.25
3.2925
For any non-zero integer a, we have
(3×102)+(2×101)+(9×100)+(2×10−1)+(5×10−2) =(3×100)+(2×10)+(9×1)+(2×110)+(5×1100) =300+20+9+0.2+0.05 =329.25
Write the numeral whose expanded form is given below:(i) 6×104+3×103+0×102+7×101+8×100(ii) 9×106+7×105+0×104+3×103+4×102+6×101+2×100(iii) 8×105+6×104+4×103+2×102+9×101+6×100