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Question

Express (3×102)+(2×101)+(9×100)+(2×101)+(5×102) as a numeral.


A

32.925

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B

3292.5

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C

329.25

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D

3.2925

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Solution

The correct option is C

329.25


For any non-zero integer a, we have

  • a0=1
  • am=1am


(3×102)+(2×101)+(9×100)+(2×101)+(5×102)
=(3×100)+(2×10)+(9×1)+(2×110)+(5×1100)
=300+20+9+0.2+0.05
=329.25


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