Express $7^{3}$ as a sum of 7 consecutive odd number.

43,45,47,49,50,53,55

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43,46,47,49,51,53,55

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43,45,47,49,51,53,55

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43,46,47,49,51,53,55

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Solution

The correct option is C
43,45,47,49,51,53,55

$7^{3}$ can be written as $49 \times 7$ = 343

keeping 49 as the mean number.

Numbers will be 43,45,47,49,51,53,55 sum of which will give 343

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Express 73 as a sum of 7 consecutive odd number.

The correct option is C 43,45,47,49,51,53,55 73 can be written as 49×7 = 343 keeping 49 as the mean number. Numbers will be 43,45,47,49,51,53,55 sum of which will give 343

Express $7^{3}$ as a sum of 7 consecutive odd number.

The correct option is C
43,45,47,49,51,53,55

$7^{3}$ can be written as $49 \times 7$ = 343

keeping 49 as the mean number.

Numbers will be 43,45,47,49,51,53,55 sum of which will give 343