Express 7-3 as a sum of 7 consecutive odd number-43-45-47-49-50-53-55-43-46-47-49-51-53-55-43-45-47-49-51-53-55-43-46-47-49-51-53-55-

The correct option is C 43,45,47,49,51,53,55 7^3 can be written as 49 × 7 = 343 keeping 49 as the mean number. Numbers will be 43,45,47,49,51,53,55 sum of ...

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Standard VIII

Mathematics

Sum of Random Consecutive Odd Numbers

Express 7^3 a...

Question

Express $7^{3}$ as a sum of 7 consecutive odd number.

43,45,47,49,50,53,55

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43,46,47,49,51,53,55

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43,45,47,49,51,53,55

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43,46,47,49,51,53,55

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Solution

The correct option is C
43,45,47,49,51,53,55

$7^{3}$ can be written as $49 \times 7$ = 343

keeping 49 as the mean number.

Numbers will be 43,45,47,49,51,53,55 sum of which will give 343

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Similar questions

Express $7^{3}$ as a sum of 7 consecutive odd number.

Express the following numbers as the sum of consecutive odd numbers:
(i) $8^{3}$ (ii) $7^{3}$

Q. Shishir is trying to express every cube as the sum of consecutive odd numbers. He is struggling to express

7^{3}

in this way. Can you find the odd numbers whose sum leads to

7^{3}

Q. While trying to express

7^{3}

as the sum of consecutive odd numbers,

7^{3}

should be divided by which number to find the middle number?

While trying to express $7^{3}$ as the sum of consecutive odd numbers, what is the number, $7^{3}$ should be divided by to find the middle number?

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Express 73 as a sum of 7 consecutive odd number.

The correct option is C 43,45,47,49,51,53,55 73 can be written as 49×7 = 343 keeping 49 as the mean number. Numbers will be 43,45,47,49,51,53,55 sum of which will give 343

Express $7^{3}$ as a sum of 7 consecutive odd number.

The correct option is C
43,45,47,49,51,53,55

$7^{3}$ can be written as $49 \times 7$ = 343

keeping 49 as the mean number.

Numbers will be 43,45,47,49,51,53,55 sum of which will give 343