Question

Express $9^3$ as the sum of 9 consecutive odd numbers.

• A. 73, 75, 77., 79, 81, 83, 85, 87, and 89.
• B. 81, 83, 85, 87, 89,91, 93,95 and 97
• C. 71, 73, 75, 77, 79, 81, 83, 85 and 87
• D. 91, 93, 95, 97, 99, 101, 103, 105 and 107

Answer 1

The correct option is A 73, 75, 77., 79, 81, 83, 85, 87, and 89.

Here, the sum of 9 consecutive odd numbers should be equal to $9^3$.
To find the odd numbers whose sum is $9^3$, we first divide $9^3$ by 9.
$\Rightarrow \frac{9^3}{9}=9^2=81$
Since 81 is an odd number, it would be middle number of the series. The other odd numbers would be the 4 odd ones before and after 81.
So the odd numbers whose sum gives $9^3$ are 73, 75, 77., 79, 81, 83, 85, 87, and 89.