Let a=l(b×c)+m(c×a)+n(a×b) ...(1) We have to find the values of l,m and n. Multiply both sides of (1) scalarly by a. a.a=la.(b×c)+ma.(c×a)+na.(a×b)
⇒a.a=l[abc]+m[aca]+n[aab]=l[abc]. ∴ Scalar triple product is zero when two vectors are equal
∴l=a.a[abc] Similarly, multiplying both sides of (1) salarly by b and c, we get m=a.b(abc),n=a.c[abc] ∴a=a.a[abc](b×c)+a.b[abc](c×a)+a.c[abc](a×b) Similarly we can write the values b and c as b=b.a[abc](b×c)+b.b[abc](c×a)+b.c[abc](a×b) and c=c.a[abc](b×c)+c.b[abc](c×a)+c.c[abc](a×b).