Express $cot 85^{\circ} + cos 75^{\circ}$ in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ} .$

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Solution

We have, $cot 85^{\circ} + cos 75^{\circ}$

$= cot (90 - 5) + cos (90 - 15) .$

$= tan 5 + sin 15$

$∴ cot 85 + cos 75 = tan 5 + sin 15$

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Similar questions

Q. Express the following in terms of trigonometric ratios of angles lying between

0^{\circ}

and

45^{\circ}

cot 85^{\circ} + cos 75^{\circ}

Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

Q. Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°

(i) sin 59° + cos 56°
(ii) tan 65° + cot 49°
(iii) sec 76° + cosec 52°
(iv) cos 78° + sec 78°
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(vi) cot 85° + cos 75°
(vii) sin 67° + cos 75°

Q. Question 7
Express

s i n 67^{\circ} + c o s 75^{\circ}

in terms of trigonometric ratios of angles between

0^{\circ}

and

45^{\circ}

Express each of the following in terms of trigonometric ratios of angles lying between 0° and 45°.

(i) sin67° + cos75°
(ii) cot65° + tan49°
(iii) sec78° + cosec56°
(iv) cosec54° + sin72°

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Express cot85∘+cos75∘ in terms of trigonometric ratios of angles between 0∘ and 45∘.

We have, cot85∘+cos75∘=cot(90−5)+cos(90−15).=tan5+sin15∴cot85+cos75=tan5+sin15

Express $cot 85^{\circ} + cos 75^{\circ}$ in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ} .$

We have, $cot 85^{\circ} + cos 75^{\circ}$

$= cot (90 - 5) + cos (90 - 15) .$

$= tan 5 + sin 15$

$∴ cot 85 + cos 75 = tan 5 + sin 15$