CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Identities

Express 1-t...

Question

Express $\frac{1 - tan x}{1 + tan x}$ in terms of $sin x$ and $cos x$

Open in App

Solution

$\frac{1 - t a n x}{1 + t a n x}$ = $\frac{1 - \frac{s i n x}{c o s x}}{1 + \frac{s i n x}{c o s x}} =$ $\frac{c o s x - s i n x}{c o s x + s i n x} .$

Suggest Corrections

thumbs-up

0

Similar questions

\frac{sec x + 1 - tan x}{tan x - sec x + 1} = \frac{1 + cos x}{sin x}

.

\frac{sec x + 1 - tan x}{tan x + sec x + 1} = \frac{1 - sin x}{cos x}

\int (\sqrt{sin x} + \sqrt{cos x})^{- 4} d x =

\frac{t a n x}{s e c x - 1} - \frac{s i n x}{1 + c o s x} =

\frac{sin x}{1 + cos x} = tan \frac{x}{2} .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trigonometric Identities_Concept

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Trigonometric Identities

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon