Question

Express :
$\frac{(3+4i)(4+3i)}{1+i}$
in the forum $x+iy$

Answer 1

$\frac{(3+4i)(4+3i)}{1+i}$

$=\frac{12+25i-12}{1+i}\times \frac{1-i}{1-i}$

$=\frac{25i(1-i)}{1^2-i^2}$

$=\frac{25i-25i^2}{1+1}$

$=\frac{25}{2}+\frac{25}{2}i$

Here $x=\frac{25}{2}=y$