Express √3−1+i(√3+1)2√2in the modulus-amplitude form
A
cos7π24+isin7π24
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B
cos5π12+isin5π12
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C
cos7π12+isin7π12
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D
cos5π24+isin5π24
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Solution
The correct option is Bcos5π12+isin5π12 Simplifying, we get √3−12√2+i(√3+1)2√2 =(cos300cos450−sin300sin450)+i(cos300sin450+sin300cos450) =cos(750)+isin750 =cos(5π12)+isin(5π2)