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Question

Express 31+i(3+1)22 in the modulus-amplitude form

A
cos7π24+isin7π24
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B
cos5π12+isin5π12
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C
cos7π12+isin7π12
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D
cos5π24+isin5π24
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Solution

The correct option is B cos5π12+isin5π12
Simplifying, we get
3122+i(3+1)22
=(cos300cos450sin300sin450)+i(cos300sin450+sin300cos450)
=cos(750)+isin750
=cos(5π12)+isin(5π2)

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