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Byju's Answer
Standard X
Mathematics
Method of Finding HCF
Express each ...
Question
Express each number as a product of its prime factors:
(i)
140
(ii)
156
(iii)
3825
(iv)
5005
(v)
7429
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Solution
(i)
140
140
=
2
×
70
=
2
×
2
×
35
=
2
×
2
×
5
×
7
(ii)
156
156
=
2
×
78
=
2
×
2
×
39
=
2
×
2
×
3
×
13
(iii)
3825
3825
=
3
×
1275
=
3
×
3
×
425
=
3
×
3
×
5
×
85
=
3
×
3
×
5
×
5
×
17
(iv)
5005
5005
=
5
×
1001
=
5
×
7
×
143
=
5
×
7
×
11
×
13
(v)
7429
7429
=
17
×
437
=
17
×
19
×
23
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Similar questions
Q.
Express each number as a product of its prime factor:
(i)
140
(ii)
156
(iii)
3825
(iv)
5005
Q.
Express each number as a product of its prime factors:
(i)
140
(ii)
156
(iii)
3825
Q.
Express each number as a product of its prime factors:
(i) 140
(ii) 156
Q.
Express the following integers as a product of its prime factors:
(i)
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(ii)
468
(iii)
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(iv)
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Q.
Question 1 (v)
Express each number as the product of its prime factors:
v) 7429
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Method of Finding HCF
Standard X Mathematics
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