Express 2−i3+i in the form a + ib
1 + i
(1 - i)
1 - i
(1 + i)
2−i3+i = 2−i3+i×3−i3−i = (6−1)+i(−3−2)9+1 = 5−5i10 = 12(1 - i)
1+2i+3i21−2i+3i2 equals