Question

Express in simplest terms: $\sqrt[3]{3\frac{27}{a^5{b}^6{c}^4}}$

• A. $\frac{1}{a{b}^{2}c}\sqrt[3]{3\frac{1}{a^{2}c}}$
• B. $\frac{3}{a{b}^{2}c}\sqrt{\frac{1}{a^{2}c}}$
• C. $\frac{1}{a{b}^{2}c}\sqrt{\frac{1}{a^{2}c}}$
• D. $\frac{3}{a{b}^{2}c}\sqrt[3]{3\frac{1}{a^{2}c}}$

Answer 1

The correct option is D $\frac{3}{a{b}^{2}c}\sqrt[3]{3\frac{1}{a^{2}c}}$

$\sqrt[3]{3\frac{27}{a^5{b}^6{c}^4}}=\sqrt[3]{3\frac{3^3}{{(a}^3{a}^2\left)\right(b^{3\ast 2}\left)\right(c\ast c^3)}}=\frac{3}{a{b}^{2}c}\sqrt[3]{3\frac{1}{a^{2}c}}$