1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Mathematics
Finding Square Root of a Number
Express in si...
Question
Express in simplest terms
8
√
512
A
8
√
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−
2
8
√
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
8
√
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
8
√
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
D
2
8
√
2
8
√
512
=
8
√
256
∗
2
=
8
√
2
8
∗
2
=
2
8
√
2
Suggest Corrections
0
Similar questions
Q.
In the sequence 1, 2, 2, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8, ..., where n consecutive terms have the value n, the 1025th term is
Q.
The constant term in the expression
(
4
x
2
−
3
x
y
−
8
)
is 8.
Q.
240
÷
8
×
512
÷
4
+
2
×
2
=
Q.
The value of
√
8
+
2
√
8
+
2
√
8
+
2
√
8
+
2
√
8
Q.
Find the number of digits
1025
t
h
term of the sequence
1
,
2
,
2
,
4
,
4
,
4
,
4
,
8
,
8
,
8
,
8
,
8
,
8
,
8
,
8
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Finding square root of a number
MATHEMATICS
Watch in App
Explore more
Finding Square Root of a Number
Standard VIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app