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Question

Express in terms of log a, log b
log((3a1b3÷b3a)

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Solution

log(b3a÷b3a)
loglog((b3)1/6a1/3÷b3/2a1/4)
log(b1/2a1/3a1/4b3/2)
log(1a712b)
((a7/12.b1)=1712logologb
(logb3/2.a1/4)
(logb3/2+loga1/4)
(3/2logb+14loga)
3/2lobb14loga

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