Question

Express in the simplest form.
$\frac{9}{10}(30+5t)+\frac{5}{6}(18t-12)$

• A. $-17+\frac{39}{2}t$
• B. $17t-\frac{39}{2}t$
• C. $(17+\frac{39}{2}t)$
• D. $17+\frac{93}{2}t$

Answer 1

The correct option is C $(17+\frac{39}{2}t)$

$\frac{9}{10}(30+5t)+\frac{5}{6}(18t-12)$
$=\frac{9}{10}\left(30\right)+\frac{9}{10}\left(5t\right)+\frac{5}{6}\left(18t\right)-\frac{5}{6}\left(12\right)$
$=27+\frac{45t}{10}+15t-10$
$=(17+\frac{39}{2}t)$