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Question

Express log105108 in terms of log102 and log103


A

15 2log102+3log103

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B

15 2log104+3log103

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C

15 2log102+log103

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D

15 log102+3log103

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Solution

The correct option is A

15 2log102+3log103


log105108 = log10(108)15

= 15 log10108

= 15 log10(22×32)

= 15 log1022+log1033

= 15 2log102+3log103


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