Question

Express $\log 144$ in terms of $\log 2$ and $\log 3$

• A. $4\log 2-2\log 3$
• B. $4\log 2+2\log 3$
• C. $4\log 2-4\log 3$
• D. $4\log 2+4\log 3$

Answer 1

The correct option is B $4\log 2+2\log 3$

$\log 144=x$
$\therefore x=\log (9\times 16)=\log 3^2\times 2^4$
$\therefore x=2\log 3+4\log 2$