Question

Express $\log 36$ in terms of $\log 2$ and $\log 3$

• A. $2\log 2+2\log 2$
• B. $2\log 2-2\log 3$
• C. $3\log 2+2\log 3$
• D. $2\log 2+2\log 3$

Answer 1

The correct option is D $2\log 2+2\log 3$

$\log 36=\log 3^2\times 2^2$
= $\log 3^2+\log 2^2$ ($\because \log ab=\log a+\log b$)
= $2\log 3+2\log 2$ ($\because \log a^b=b\log a$)