Express positive exponents 57-3 and 2-5

The positive exponent is obtained by reversing the #10;given term which makes the power positive. #10; #10;Therefore, the positive exponent of ( #1 ...

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Standard VII

Mathematics

Power of a Power

Express posit...

Question

Express positive exponents ${(\frac{5}{7})}^{- 3}$ and $2^{- 5}$

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Solution

The positive exponent is obtained by reversing the given term which makes the power positive.

Therefore, the positive exponent of ${(\frac{5}{7})}^{- 3}$ is,

${(\frac{7}{5})}^{3} = \frac{7^{3}}{5^{3}}$

The positive exponent of ${(2)}^{- 5}$ is,

${(\frac{1}{2})}^{5} = \frac{1}{2^{5}}$

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Express positive exponents(57)−3 and 2−5

The positive exponent is obtained by reversing the given term which makes the power positive. Therefore, the positive exponent of (57)−3 is, (75)3=7353 The positive exponent of (2)−5 is, (12)5=125

Express positive exponents ${(\frac{5}{7})}^{- 3}$ and $2^{- 5}$

The positive exponent is obtained by reversing the given term which makes the power positive.

Therefore, the positive exponent of ${(\frac{5}{7})}^{- 3}$ is,

${(\frac{7}{5})}^{3} = \frac{7^{3}}{5^{3}}$

The positive exponent of ${(2)}^{- 5}$ is,

${(\frac{1}{2})}^{5} = \frac{1}{2^{5}}$