Question

Express $\sec \theta$ in terms of $\cot \theta$

Answer 1

We know that $sec\theta =\frac{1}{cos\theta }$

We can convert it into

$=\frac{sin\theta }{cos\theta }.\frac{1}{sin\theta }$

$=\frac{1}{cot\theta }cosec\theta$

So,

$sec\theta =\frac{1}{cot\theta }{(1+cot\theta )}^{\frac{1}{2}}$