Question

express tan A in terms of sin A

Answer 1

$$\begin{gathered} \mathrm{We}\mathrm{know}\mathrm{that}, \\ \tan \mathrm{A}=\frac{\sin \mathrm{A}}{\cos \mathrm{A}} \\ \Rightarrow \tan \mathrm{A}=\frac{\sin \mathrm{A}}{\sqrt{1-{\sin }^2\mathrm{A}}} \end{gathered}$$