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Question

Express the log(a3c5b2) in terms of loga,logb, and logc.

A
32loga5logc2logb
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B
3loga5logc2logb
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C
32loga5logc23logb
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D
32loga5logclogb
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Solution

The correct option is D 32loga5logc2logb
We know that logAB=logA+logB
And logAB=logAlogB
Also, logab=bloga

So, log(a3c5b2)=loga3logc5b2
=32loga5logc2logb

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