wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Express the log(a3c5b2) in terms of loga,logb, and logc.

A
32loga5logc2logb
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3loga5logc2logb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32loga5logc23logb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32loga5logclogb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 32loga5logc2logb
We know that logAB=logA+logB
And logAB=logAlogB
Also, logab=bloga

So, log(a3c5b2)=loga3logc5b2
=32loga5logc2logb

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Logarithm with Use
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon