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Question

Express the following as the sum of two consecutive integers
1.212
2.132
3.112
4.192

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Solution

In all the cases ,
let one integer be x
since the integers are consecutive,
other integer = x + 1

Now,

a) (x) + (x + 1) = 21²
2x + 1 = 441
2x = 440
x = 440/2 = 220. and x+1 = 221
So,
the integers are 220 and 221

b) 13²
x + x + 1 = 13²
2x + 1 = 169
2x = 168
x = 168/2 = 84. and x + 1 = 85

So,
the consecutive integers are 84 and 85

c) 11²
x + x + 1 = 11²
2x + 1 = 121
2x = 120
x = 120/2
x = 60. and x + 1 = 61

So,
the consecutive integers are 60 and 61

d) 19²
x + x + 1 = 19²
2x + 1 = 361
2x = 360
x = 360/2
x = 180. and x + 1 = 181

So,
the consecutive integers are 180 and 181



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