Express the following as the sum or difference of the trigonometric ratios.
$2 s i n θ \cdot cos 2 θ$

Open in App

Solution

Using compound angle formula, $2 sin A cos B = sin (A + B) + sin (A - B)$
$2 sin θ cos 2 θ$
$= sin (θ + 2 θ) + sin (θ - 2 θ)$
$= sin (3 θ) + sin (- θ)$
$= sin 3 θ - sin θ$

Suggest Corrections

Similar questions

2 sin 4 θ \cdot cos 2 θ

2 sin 2 θ \cdot cos 4 θ

2 sin 2 θ \cdot sin 4 θ

2 cos 2 θ \cdot cos 4 θ

\sqrt{3} cos θ - sin θ

\sqrt{3} cos θ - sin θ

0 a n d 45^{0}

cos 78^{0} + sec 78^{0}

0^{\circ} a n d 45^{\circ}

s i n 72^{\circ} + c o t 72^{\circ}

Join BYJU'S Learning Program