Express the following equations in exponential form:
(A) ${log}_{6} 36 = 2$
(B) ${log}_{10} (\frac{1}{10}) = - 1$

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Solution

Given, ${log}_{6} 36 = 2$
$\Rightarrow 6^{2} = 36$
Given, ${log}_{10} (\frac{1}{10}) = - 1$
$\Rightarrow 10^{- 1} = \frac{1}{10}$

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