Question

Express the following equations in exponential form:
(A) ${\log }_{6}36=2$
(B) ${\log }_{10}\left(\frac{1}{10}\right)=-1$

Answer 1

Given, ${\log }_{6}36=2$

$\Rightarrow 6^2=36$
Given, ${\log }_{10}\left(\frac{1}{10}\right)=-1$

$\Rightarrow {10}^{-1}=\frac{1}{10}$