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Question

Express the following expression in the form of a + ib

(3+5i)(35i)(3+2i)(32i)

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Solution

(3+5i)(35i)(3+2i)(32i)

=(3)2(5i)23+2i3+2i

=95i222i=9522i=1422i=72i

=72i×ii=72i2=7i2=72i2


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