Express the following in exponential form
(i) ${log}_{2} 128 = 7$
(ii) ${log}_{10} 0.0001 = - 4$
(iii) ${log}_{8} 16 = \frac{4}{3}$

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Solution

$1) {log}_{2} 128 = 7 ⟹ 2^{7} = 128$

$2) {log}_{10} 0.0001 = - 4 ⟹ 10^{- 4} = 0.0001$

$3) {log}_{8} 16 = \frac{4}{3} ⟹ 8^{4 / 3} = 16$

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