Question

Question 2
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
$\left(i\right)2x+3y=9.35\left(ii\right)x-\frac{y}{5}-10=0\left(iii\right)-2x+3y=6\left(iv\right)x=3y$
$\left(v\right)2x=-5y\left(vi\right)3x+2=0\left(vii\right)y-2=0\left(viii\right)5=2x$

Answer 1

$\left(i\right)2x+3y=9.35$
$\Rightarrow 2x+3y-9.35=0$
On comparing this equation with $ax+by+c=0,$ we get,
$a=2,b=3andc=-9.35$

$\left(ii\right)x-\frac{y}{5}-10=0$
On comparing this equation with $ax+by+c=0$, we get,
$a=1,b=\frac{-1}{5}andc=-10$
$\left(iii\right)-2x+3y=6$
$\Rightarrow -2x+3y-6=0$
On comparing this equation with $ax+by+c=0$, we get,
$a=-2,b=3andc=-6$
$\left(iv\right)x=3y$
$\Rightarrow x-3y=0$
On comparing this equation with $ax+by+c=0,$ we get,
$a=1,b=-3andc=0$
$\left(v\right)2x=-5y$
$\Rightarrow 2x+5y=0$
On comparing this equation with $ax+by+c=0$, we get,
$a=2,b=5andc=0$
$\left(vi\right)3x+2=0$
$\Rightarrow 3x+0y+2=0$
On comparing this equation with $ax+by+c=0,$ we get,
$a=3,b=0andc=2$
$\left(vii\right)y-2=0$
$\Rightarrow 0x+y-2=0$
On comparing this equation with $ax+by+c=0$, we get,
$a=0,b=1andc=-2$
$\left(viii\right)5=2x$
$\Rightarrow -2x+0y+5=0$
On comparing this equation with $ax+by+c=0,$ we get,
$a=-2,b=0andc=5$