Question

Express the following surds as pure surds.

$\frac{4}{3}\sqrt{6}$

• A. $\sqrt{\frac{32}{3}}$
• B. $\sqrt{\frac{31}{2}}$
• C. $\sqrt{\frac{31}{3}}$
• D. $\sqrt{\frac{32}{2}}$

Answer 1

Answer: (A)

$\sqrt{\frac{32}{3}}$

Mixed surds can be expressed in the form of pure surds.

Because if we make rational co-efficient under radical sign, it will become a pure surd.

$\frac{4}{3}\sqrt{6}=\sqrt{\frac{16\left(6\right)}{9}}=\sqrt{\frac{32}{3}}$