Question

Express the following with positive exponents:
${\left(\frac{4}{7}\right)}^{-3}$

Answer 1

${\left(\frac{4}{7}\right)}^{-3}=\frac{4^{-3}}{7^{-3}}$ ($a^{-m}=\frac{1}{a^m}$ and $a^m=\frac{1}{a^{-m}}$)
$=\frac{7^3}{4^3}={\left(\frac{7}{4}\right)}^3$