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Question

Express the ratios cos A and sin A respectively in terms of tan A.

A
tan A1+tan2A,11+tan2A
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B
11+tan2A,tan A1+tan2A
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C
tan A1tan2A,11tan2A
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D
11tan2A,tan A1tan2A
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Solution

The correct option is A tan A1+tan2A,11+tan2A
We know that
tan2A+1=sec2AsecA=tan2A+1.
As secA and cosA are reciprocals of each other,
we can directly write the value of cosA as:
cos A=11+tan2A and from the identity sin2A+cos2A=1
we can get the value of sinA.
sinA=1cos2A.
Substitute value of cosA=11+tan2A in the above equation.
sinA=1(11+tan2A)2
=111+tan2A
=1+tan2A11+tan2A
=tan2A1+tan2A
sinA=tanA1+tan2A and cosA=11+tan2A

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