Express these rational numbers as decimals. 1: (-2/3) 2: (1/7) 3: (17 5/6) 4: (5/6)

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Solution

Dear Student,
1.
-2/3 = -0.66666....
2.
1/7 = 0.1428571429....
3.
$17 \frac{5}{6} = \frac{107}{6}$ = 17.833333...
4.
5/6 = 0.8333333...
Regards!

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Similar questions

Two rational numbers between $\frac{2}{3}$ and $\frac{5}{3}$ are

(a) $\frac{1}{6}$ and $\frac{2}{6}$
(b) $\frac{1}{2}$ and $\frac{2}{1}$
(c) $\frac{5}{6}$ and $\frac{7}{6}$
(d) $\frac{2}{3}$ and $\frac{4}{3}$

Express each of the following as a rational number in the form $\frac{p}{q} :$

$(i) 6^{- 1} (i i) (- 7)^{- 1} (i i i) {(\frac{1}{4})}^{- 1} (i v) (- 4)^{- 1} \times {(\frac{- 3}{2})}^{- 1} (v) {(\frac{3}{5})}^{- 1} \times {(\frac{5}{2})}^{- 1}$

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Question 6

Using commutativity and associativity of addition of rational numbers, express each of the following as a rational number:

(i) $\frac{2}{5} + \frac{7}{3} + \frac{- 4}{5} + \frac{- 1}{3}$

(ii) $\frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9}$

(iii) $\frac{2}{5} + \frac{8}{3} + \frac{- 11}{15} + \frac{4}{5} + \frac{- 2}{3}$

(iv) $\frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{21}$

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Express these rational numbers as decimals. 1: (-2/3) 2: (1/7) 3: (17 5/6) 4: (5/6)

Dear Student, 1. -2/3 = -0.66666.... 2. 1/7 = 0.1428571429.... 3. 1756= 1076 = 17.833333... 4. 5/6 = 0.8333333... Regards!

Dear Student,
1.
-2/3 = -0.66666....
2.
1/7 = 0.1428571429....
3.
$17 \frac{5}{6} = \frac{107}{6}$ = 17.833333...
4.
5/6 = 0.8333333...
Regards!