Question

Express y in terms of x, given that $\frac{x}{5}+2y=3$. Check whether (−5, 2) is a solution of the given equation.

Answer 1

Given: $\frac{x}{5}+2y=3$
$\Rightarrow x+10y=15$

$\Rightarrow y=\frac{15-x}{10}$

We have to check whether $(-5,2)$ is a solution of the given equation.
So,
$LHS=\frac{x}{5}+2y=\frac{-5}{5}+2\times 2=-1+4=3=RHS$
Hence, $(-5,2)$ is a solution of the given equation.