Question

Express y in terms of x in the equation :

- 3x + 5y - 11 = 0, Find the point where the time represented by - 3x + 5y - 11 = 0 cuts y axis.

Answer 1

$$\begin{gathered} \mathrm{The}\mathrm{given}\mathrm{equation}\mathrm{is}, \\ -3\mathrm{x}+5\mathrm{y}-11=0 \\ \Rightarrow 5\mathrm{y}=3\mathrm{x}+11 \\ \Rightarrow \mathbf{y}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{3}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{11}}{\mathbf{5}} \\ \mathrm{Now},\mathrm{put}\mathrm{x}=0\mathrm{in}\mathrm{the}\mathrm{above}\mathrm{equatio},\mathrm{we}\mathrm{get} \\ \mathrm{y}=\frac{3\times 0+11}{5}=\frac{11}{5} \\ \mathbf{So}\mathbf{,}\mathbf{}\mathbf{the}\mathbf{}\mathbf{above}\mathbf{}\mathbf{line}\mathbf{}\mathbf{cut}\mathbf{}\mathbf{y}\mathbf{-}\mathbf{axis}\mathbf{}\mathbf{at}\mathbf{}\left(\mathbf{0}\mathbf{,}\mathbf{}\frac{\mathbf{11}}{\mathbf{5}}\right) \end{gathered}$$