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Conduction

Expression an...

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Expression and derivation of equivalent thermal conductivity K in parallel and series.

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Q. Statement 1 : Equivalent thermal conductivity of two rods of same physical dimensions and having same thermal conductivity

(k)

connected to each other in parallel combination is equal to

k

.
Statement 2 : Equivalent thermal conductivity of two rods of same physical dimensions and having same thermal conductivity

(k)

, connected to each other in series combination is equal to

k

.

Q. Assertion :The equivalent thermal conductivity of two plates of same thickness in series is less than the smaller value of thermal conductivity. Reason: For two plates of equal thickness in series the equivalent thermal conductivity is given by

\frac{1}{K} = \frac{1}{K_{1}} + \frac{1}{K_{2}}

Q. Two rods of the same length and diameter having thermal conductivities

K_{1} K_{2}

are joined in parallel. The equivalent thermal conductivity of the combination is:

Q. Two metallic slabs of same area of cross section and length having thermal conductivities

300 {W/m}^{\circ} C

200 {W/m}^{\circ} C

respectively are connected in series combination. Find the equivalent thermal conductivity (in

{W/m}^{\circ} C

)

Q. A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities

K_{1}

K_{2}

. The equivalent thermal conductivity of the slab is :

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