Question

Extra very pure ${\mathrm{N}}_2$ can be obtained by heating _____

Answer 1

Pure Nitrogen preparation:

• When Sodium or Barium azide is heated, it produces exceedingly pure Nitrogen.
• Sodium azide is heated at $573\mathrm{K}$ and forms Sodium and pure Nitrogen gas
• Here since the sodium produced is in the solid-state the nitrogen gas will be highly pure.

$\underset{\mathrm{Sodium}\mathrm{azide}}{2{\mathrm{NaN}}_3\left(\mathrm{s}\right)}\stackrel{573\mathrm{K}}{\to }\underset{\mathrm{Sodium}}{2\mathrm{Na}\left(\mathrm{s}\right)}+\underset{\mathrm{Pure}\mathrm{Nitrogen}\mathrm{gas}}{3{\mathrm{N}}_2\left(\mathrm{g}\right)}$

• Azide salt of barium can be obtained in the purest form and it produces barium as a solid and nitrogen gas when heated.

$\underset{\mathrm{Barium}\mathrm{azide}}{\mathrm{Ba}{\left({\mathrm{N}}_3\right)}_2\left(\mathrm{s}\right)}\stackrel{\mathrm{Heat}}{\to }\underset{\mathrm{Barium}}{\mathrm{Ba}\left(\mathrm{s}\right)}+\underset{\mathrm{Pure}\mathrm{Nitrigen}\mathrm{gas}}{3{\mathrm{N}}_2\left(\mathrm{g}\right)}$

• As a result, no additional filtration is required.

Therefore, Extra very pure ${\mathrm{N}}_2$ can be obtained by heating Sodium azide ($\mathrm{Na}{\left(\mathrm{N}\right)}_3$) or Barium azide ($\mathrm{Ba}{\left({\mathrm{N}}_3\right)}_2$)