Extraction of aluminium from oxide $(A l_{2} O_{3})$ is best done by:

Electrolytic reduction of

A l_{2} O_{3}

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Reduction of

A l_{2} O_{3}

with carbon

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Reduction of

A l_{2} O_{3}

with sodium

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Reduction of

A l_{2} O_{3}

with CO

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Solution

The correct option is A Electrolytic reduction of $A l_{2} O_{3}$
Electrolytic reduction of alumina: Pure alumina melts at about $2000^{o} C$ and is a bad conductor of electricity. If fused cryolite and fluorspar are added, the mixture melts at $900^{o} C$ and $A l_{2} O_{3}$ becomes a good conductor of electricity. Metallic Al is liberated at the cathode. So extraction of $A l_{2} O_{3}$ is best done by electrolytic reduction.

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Similar questions

Q. Extraction of aluminium from aluminium oxide

(A l_{2} O_{3})

is best done by :

Coke does cause reduction of $A l_{2} O_{3}$ .
$Δ G_{f}^{\circ}$ (in $k J m o l^{- 1}$ ) for $\begin{matrix} A l_{2} O_{3} & : & - 1582 C O & : & - 137.2 \end{matrix}$

Q. The Gibb's energy for the decomposition of

A l_{2} O_{3}

500^{0} C

is as follows :

\frac{2}{3} A l_{2} O_{3} ⟶ \frac{4}{3} A l + O_{2}

△_{r} G = + 960 k J m o l^{- 1}

The potential difference needed for the electrolytic reduction of aluminium oxide

(A l_{2} O_{3})

500^{0} C

at least:

$A l_{2} O_{3}$ can be converted to anhydrous $A l C l_{3}$ by heating.

Q. Aluminium oxide,

A l_{2} O_{3}

is:

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Extraction of aluminium from oxide (Al2O3) is best done by:

Extraction of aluminium from oxide $(A l_{2} O_{3})$ is best done by: