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Question

f:[1,1][1,1] is defined by f(x)=x|x|. This function is

A
one-one but not onto
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B
onto but not one-one
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C
neither one - one nor onto
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D
bijective
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Solution

The correct option is B bijective
f(x)=xx
={x2,x>0x2,x<0
f(x) is one - one & onto in its domain.
f(x) is bijective.

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