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Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
f - 3=f0=0 wh...
Question
f
(
−
3
)
=
f
(
0
)
=
0
where f is second degree polynomial find its min value
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Solution
P
second descee polynimial
f
(
0
)
=
f
(
−
3
)
=
0
⇒
root
=
−
3
,
0
min value at
−
3
+
0
2
=
−
1.5
f
(
x
)
=
x
(
x
+
3
)
−
3
2
(
+
3
2
)
=
−
9
/
4
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Similar questions
Q.
f
(
x
)
is a polynomial of degree 2,
f
(
0
)
=
4
,
f
′
(
0
)
=
3
and
f
′′
(
0
)
=
4
, then
f
(
−
1
)
is equal to
Q.
The second degree polynomial
f
(
x
)
, satisfying
f
(
0
)
=
0
,
f
(
1
)
=
1
,
f
′
(
x
)
>
0
∀
x
ϵ
(
0
,
1
)
.
Q.
Let
f
(
x
)
be a polynomial of degree
2
satisfying
f
(
0
)
=
1
,
f'(0)=-2
a
n
d
f
′′
(
0
)
=
6
,
then
∫
2
−
1
f
(
x
)
d
x
is equal to
Q.
Evaluate
∫
f
(
x
)
x
3
−
1
d
x
, where
f
(
x
)
is a polynomial of degree
2
in
x
such that
f
(
0
)
=
f
(
1
)
=
3
f
(
2
)
=
−
3
Q.
Let
f
(
x
)
=
(
x
3
+
2
)
30
. If
f
n
(
x
)
is a polynomial of degree
20
, where
f
n
(
x
)
denotes the
n
t
h
derivative of
f
(
x
)
w.r.t.
x
, then the value of
n
is-
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