F - 32 - 9-5CChange the subject of the above formula to - a C- b F-

We have F 32 = 9/5C a) = gt; C = 5/9 (F 32) b) F = #160; 9/5C + 32 ...

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Byju's Answer

Standard XII

Mathematics

Polynomial Functions

F - 32 = 9/5C...

Question

$F - 32 = \frac{9}{5} C$
Change the subject of the above formula to :
(a) C, (b) F.

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Solution

We have $F - 32 = \frac{9}{5} C$
a) $=> C = \frac{5}{9} (F - 32)$
b) $F = \frac{9}{5} C + 32$

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Similar questions

F = \frac{9}{5} C + 32

; make 'C' the subject of formula.

$F = \frac{9}{5} C + 32$ .

Make C as the subject of formula

C = \frac{5}{9} (F - 32)

Making F as the subject, form a formula for the statement given above.

F - 32 = \frac{9}{5} C

; Given

C = 40^{\circ}

, find F.

A solution is to be kept between $68^{\circ} F$ and $77^{\circ} F$ . What is the range of temperature in degree Celsius (C) if the Celsius /Fahrenheit (F) convension formula is given by $F = \frac{9}{5} C + 32$ ?

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F−32=95CChange the subject of the above formula to : (a) C, (b) F.

We have F−32=95Ca) =>C=59(F−32)b) F=95C+32

$F - 32 = \frac{9}{5} C$
Change the subject of the above formula to :
(a) C, (b) F.

We have $F - 32 = \frac{9}{5} C$
a) $=> C = \frac{5}{9} (F - 32)$
b) $F = \frac{9}{5} C + 32$