$f (c)$ is a maximum value of $f (x)$ when at $x = c$

f^{'} (x)

changes sign from +ve to -ve

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f^{'} (x)

d changes sign from -ve to +ve

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f^{'} (x)

does not change sign

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f^{'} (x)

is zero

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Solution

The correct option is A $f^{'} (x)$ changes sign from +ve to -ve
$f (c)$ is the minimum value of $y = f (x)$ if
$f^{'} (c) = 0$ and $f^{''} (c) > 0$ .

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f(c) is a maximum value of f(x) when at x=c

The correct option is A f′(x) changes sign from +ve to -vef(c) is the minimum value of y=f(x) if f′(c)=0 and f′′(c)>0.

$f (c)$ is a maximum value of $f (x)$ when at $x = c$

The correct option is A $f^{'} (x)$ changes sign from +ve to -ve
$f (c)$ is the minimum value of $y = f (x)$ if
$f^{'} (c) = 0$ and $f^{''} (c) > 0$ .