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B
f′(x) changes sign from −ve to +ve
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C
f′(x) does not change sign
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D
f′(x) is zero
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Solution
The correct option is Bf′(x) changes sign from −ve to +ve f(c) is the minimum value of y=f(x) if f′(c)=0 and f′′(c)>0. That is slope of y=f′(x) changes from negative to positive at x=c.